Hmm, I didn't even look at the storage claim... so let's do so.
1000 L of water = 1000 kg
Heat capacity of water = 4.18 kJ/kg.degC
Max temperature 200 deg C
Ambient temperature 20 deg C (let's say ~ avg for Brisbane?)
Temperature difference = 180 deg C
Max stored heat = 1000 * 4.18 * 180 = 752400 kJ = 209 kWh
209 kWh / 3 days = 69.7 kWh/d
Promises made ~ 180 kWh/d (electricity + AC + hot water)
Even ignoring the AC and hot water and using the "bankable" 120 kWh/d electricity we'd be at a substantial deficit... and that's if we could assume 100% efficiency converting the stored heat energy into the other useful forms... which is also impossible if we want to obey the laws of thermodynamics.
Let me know when you're ready to commit to a firm view.
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